The product calls a thread's run() method instead of calling start(), which causes the code to run in the thread of the caller instead of the callee.
In most cases a direct call to a Thread object's run() method is a bug. The programmer intended to begin a new thread of control, but accidentally called run() instead of start(), so the run() method will execute in the caller's thread of control.
Threat Mapped score: 0.0
Industry: Finiancial
Threat priority: Unclassified
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Phase | Note |
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Implementation | N/A |
Intro: The following excerpt from a Java program mistakenly calls run() instead of start().
Thread thr = new Thread() { public void run() { ... } }; thr.run();